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Introduction:

Mathematics Literacy is a subject that focuses on practical applications of mathematics in everyday life. Grade 12 Mathematics Literacy is an important subject as it prepares students for real-world situations where mathematical concepts and skills are applied. Paper 2 of the Grade 12 Mathematics Literacy exam consists of a memorandum that provides solutions to the exam questions.

See also  Agricultural sciences grade 12 question papers and memorandums pdf download

How to access the question papers:

The Grade 12 Mathematics Literacy exam papers and memoranda are available on various educational websites and online resources. Students can also access these papers through their school or teacher.

Subtopics and possible questions:

Paper 2 of the Grade 12 Mathematics Literacy exam covers various subtopics, including:

  • Financial maths
  • Measurement
  • Data handling

Possible questions in the exam could include:

  • Calculating interest and repayment amounts on loans
  • Converting between different units of measurement
  • Interpreting and drawing graphs
  • Analyzing data sets and calculating measures of central tendency

How to prepare for exams:

To prepare for the Grade 12 Mathematics Literacy exam, students should:

  1. Practice past exam papers: Use past exam papers to familiarize yourself with the exam format and the types of questions that may be asked. This will also help you identify areas where you need to improve.
  2. Study regularly: Allocate regular study time for Mathematics Literacy and stick to your study schedule. Review concepts and practice calculations regularly.
  3. Seek help: If you are struggling with any concepts or calculations, seek help from your teacher, tutor, or classmates.
  4. Memorize formulas and definitions: Memorize formulas and definitions as these are essential for solving mathematical problems.
  5. Stay focused during the exam: During the exam, read the instructions carefully, manage your time, and stay focused on the task at hand.

NATIONAL
SENIOR CERTIFICATE
GRADE 12
JUNE 2022
MATHEMATICAL LITERACY P2
MARKING GUIDELINE
MARKS: 100

Symbol Explanation
M Method
M/A Method with accuracy
MCA Method with Consistent Accuracy
CA Consistent Accuracy
A Accuracy
C Conversion
S Simplification
RT/RG/RM Reading from a table OR Reading from a graph OR Read from map
F Choosing the correct formula
SF Substitution in a formula
J Justification
P Penalty, e.g for no units, incorrect rounding off etc
R Rounding off OR Reason
AO Answer only
NPR No penalty for rounding
QUESTION 1 [20]
Ques. Solutions Explanation level
1.1.1 Mozambique ✓✓ 2RT correct country (2) L1
Maps
1.1.2 3 ✓✓ 2A no of tented camps (2) L1
Maps
1.1.3 9 ✓✓ 2A correct number (2) L1
Maps
1.1.4 Main camp ✓✓ 2A type of camp (2 L1
Maps
1.2.1 260 ÷ 10 ✓
26cm
1C dividing by 1 000
1A answer (3)
L1
Meas.
1.2.2 150 − 40 ✓
110mm ÷ 1000
0.11m✓
1MA subtraction
1C dividing by 1000
1A answer (3)
L1
Meas.
1.2.3 100:150 ✓✓
2:3 ✓
1RT correct valu4es
1MA ration concept
1S simplification
L1
Meas.
1.3.1 14 × 2 + 3✓
31✓
1MA multiplication
and addition
1A answer (2)
L1
Meas.
1.3.2 6✓✓ 2A (2) L1
Probl
[20]
QUESTION 2 [32]
Ques. Solutions Explanations Level
2.1.1 Distance = 1 029 km ✓
1 029 x 1 000 ✓
1 029 000 m ✓
1RT correct distance
1C conversion
1CA answer (3)
L2
Maps
2.1.2 Cape Town to Johannesburg = 1 402 km ✓
Johannesburg to Bloemfontein = 417 km ✓
Total = 1 402 + 417
= 1 819 km ✓
Cape Town to Nelspruit = 1 779 km ✓
Difference = 1 819 – 1 779 = 40 km ✓ Valid ✓
1RT distance CT to
Johannesburg
1RT distance to Bloem
1CA total distance
1RT Nelspruit
1CA difference
1O valid
L4
Maps
2.1.3 Distance = 1 393 km ✓
Distance = Speed x Time
1 393 = 105 x T ✓
T = 1 393/105 ✓
T = 13,2666 hrs
= 0,2666 x 60 ✓
= 16 min
T = 13hrs 16 min + 2 hrs 30min ✓
= 15hrs 46min ✓
1RT correct distance
1A substitution
1S simplification
1C hours to minutes
1M adding times
1CA answer
(6)
L3
Maps
2.2.1 Bar scale ✓ 1A type of scale (2) L1
Maps
2.2.2 Scale 1,2 cm = 5 km ✓
4,3 cm = 5 x 4,3 ✓
= 21,5 ✓
1,2
= 17,916666 x 1 000
= 1 7 917 m ✓
1A measuring the
scale
Accept 1,1 cm–1,3 cm
1A measuring the map
Accept 4,1 cm–4,4 cm
1S simplification
1CA distance in
metres (4)
L3
Maps
2.2.3 South East ✓✓ 2A direction (2) L2
Maps
2.2.4 2 850 = 870
870 ✓
2 850
0,30526 x 100 ✓
30,526 ✓
= 30,53 cm ✓
1MA dividing by 2 850
1C to cm
1CA answer
1R rounding to two
decimals (4)
L2
Maps
2.2.5 Fuel consumed:
10 km = 1litre
1 km = 1 litre
10
litre
Therefore 929 km will require: 929 × 1/10 litre ✓M
= 929 ÷ 10
= 92,9 litre ✓ A
Cost of return journey = 2 (92,9 × R16,98) ✓ M
= 2 (R1 577,442)
= R3 154, 884 ✓ S
= R3 154, 88 ✓ CA
1M Determine litres
1A correct answer
1M using 929 km
1S simplifying
CA correct answer
L2
Maps
[32] L3
Maps
QUESTION 3 [29]
Ques. Solutions Explanations Level
3.1.1 274 +15,25 + 15,25 ✓✓
= 304,5 cm ✓
OR
274 + 2(15,25) ✓
274 + 30,5 ✓
= 304,5 cm ✓
1RT all values correct
1MA adding overhang
1CA answer
L1
Meas.
3.1.2 274 – 152,5 ✓
121,5 x 10 ✓
1 215 mm ✓
OR
(274 x 10) – (152,5 x 10) ✓
= 2 740 – 1 525 ✓
= 1 215 mm ✓
1MA subtraction
1C to mm
1CA answer
L2
Meas.
3.1.3 10:08 + 1:58 ✓
11:66 ✓
12:06 ✓
1MA adding time
1S simplification
1A correct time
L2
Meas.
3.1.4 76 + 15,25 ✓
= 91,25
152,5 – 91,25 ✓
= 61,25 ✓ Not valid ✓
1MA addition
1MA subtraction
1A answer
1O not valid (4)
L4
Meas.
3.2.1 100 +40 + 40 + 60 + 20 + 60 + 60 +120+20 +40 ✓✓
= 560 cm ✓
1A all values correct
1MA adding all values
1A answer (3)
L1
Meas.
3.2.2 Area = Length x Width
FIGURE 1 = 100 x 40
= 4 000 cm2
FIGURE 2 = 20 x 60
= 1 200 cm2
FIGURE 3 = 120 x 40
= 4 800 cm2
Total area = 4 000 + 1 200 + 4 800
= 10 000 / 10 000 ✓
= 1 m2 ✓
1A area 1
1A area 2
1A area 3
1MA total area
1CA area in square
metres
L2
Meas.
3.2.3 Area to paint = 1 x 2 x 2 ✓
= 4 m2
Litres needed = 4 ✓
6,2
= 0,645 ✓
= 0,65 m2
1 MA multiplying by
coats and no. of shapes
1 CA area to be painted
1 S simplification
1 CA no of litres
1 R rounding (5)
L3
Meas.
3.2.4 0,65 x 1 000 ✓
= 650 mℓ ✓
Valid ✓
1 MCA multiplying by
1 000
1 CA simplification
1 O verification (3)
L4
Meas.
[29]
QUESTION 4 [19]
Ques Solutions Explanations Level
4.1.1 17 x 100 ✓✓
255= 6,67% ✓
1A numerator
1A denominator
1CA percentage
NPR (3)
L2
Prob
4.1.2 D44 ✓ ✓ 1A letter
1A number (2)
L1
Maps
4.1.3 D = 29 ✓
E = 32 ✓
H = 41 ✓
Total = 29 + 32 +41 = 102 ✓
3A all rows 1 mark for
each row
1A correct total (4)
L2
Maps
4.2.1 29,9 ✓✓ 2RT correct amount (2) L1
Meas
4.2.2 (height)2 x BMI = Weight
1,7 x 1,7 x BMI = 95 ✓
2,89 x BMI = 95
BMI = 95/2,89 ✓
= 32,87 ✓
Obese / High health risk. Not valid ✓
1SF substitution
1S simplification
1CA
1O verification (4)
L4
Meas
4.2.3 Exercise ✓✓
Eat healthy food ✓✓
OR
Any other relevant answer.
2A
2A
2 for each suggestion
(4)
L4
Meas
[19]
Total:100

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